# A stationary proton ( q = 1.60 * 10^19 ) is located between the poles of a horseshoe magnet,...

## Question:

A stationary proton ( q = 1.60 * 10{eq}^{19} {/eq} ) is located between the poles of a horseshoe magnet, where the magnetic field is 0.15 T. What is the magnitude of the magnetic force acting on the proton?

## Magnetic Force:

Magnetic force is a fundamental force in nature. It acts only on charged and magnetic objects. The magnetic force exerted by a magnetic field on a charged object depends on the charge of that object, its speed and direction of motion, and the direction and strength of the magnetic field.

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## Answer and Explanation: 1

We've been given the following information:

- The magnitude of the magnetic field, {eq}B=0.15\;\rm T {/eq}

- The charge of a proton, {eq}q=1.60\times 10^{-19}\;\rm C {/eq}.

- The proton is stationary.

The magnitude of the magnetic force on a charged particle is given by the equation:

{eq}F=qvB \sin\,\theta {/eq}, where,

- {eq}F {/eq} is the magnitude of the force on the charged particle.

- {eq}v {/eq} is the speed of the particle.

- {eq}B {/eq} is the magnitude of the magnetic field.

- {eq}q {/eq} is the charge on the particle (without sign).

- {eq}\theta {/eq} is the angle between velocity and the magnetic field.

As the given proton is stationary, its speed is {eq}v=0 {/eq}, and the magnetic force acting on it is:

{eq}F=q\left ( 0\right )vB\sin\theta=\boxed{\mathbf{0}} {/eq}

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Chapter 18 / Lesson 7Magnetism and electricity are closely related. When current flows in a wire, a magnetic field is generated. In this lesson, we will explore how magnetic fields can exert forces on parallel current-carrying wires.