A steel wire has a length of 0.700 m and a mass of 4.300 x 10^{-3} kg. To what tension must this...

Question:

A steel wire has a length of 0.700 m and a mass of 4.300 x 10{eq}^{-3} {/eq} kg. To what tension must this wire be stretched in order that the fundamental vibration corresponds to middle C (frequency = 261.6 Hz)?

Frequency of a String:

The type of waves that a string where it reaches fundamental frequency is called a standing wave. Frequency is defined as the rate of the number of wavelengths that passes through a point. A wavelength is defined as the length of a complete wave.

Answer and Explanation:

To solve this, we can use the equation for fundamental frequency, which is given by:

{eq}f = \frac{1}{2L}\sqrt{\frac{T}{u}} {/eq}

where:

  • T is the...

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