A stone is thrown directly upward with an initial speed of 7.8 \frac{m}{s} from a height of 11 m....

Question:

A stone is thrown directly upward with an initial speed of 7.8 {eq}\frac{m}{s}{/eq} from a height of 11 m. What is the speed of the stone in {eq}\frac{m}{s}{/eq} when it hits the ground? Use {eq}g = 9.8 \frac{m}{s^2}{/eq}. Round to two decimal places.

Equations Of Motion.

There are three equations of motion:

  • {eq}v= u +a \times t {/eq}
  • {eq}s= u \times t +\dfrac{a \times t^{2}}{2} {/eq}
  • {eq}v^{2}=u^{2}+2 \times a \times s {/eq}

Where , u=initial velocity.

v = final velocity.

s = displacement.

t= time taken.

a= acceleration.

Answer and Explanation: 1

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Constant terms used in the answer are:

  • u= initial velocity of the stone = 7.8 m/s
  • h= height of the building = 11 m
  • g= acceleration due to gravity =...

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Kinematic Equations: List & Example

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Chapter 4 / Lesson 15
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What are kinematic equations of motion and their assumptions? Learn to derive the 5 kinematic equations and see applications of the kinematics formulas.


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