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A student places her 440 g physics book on a frictionless table. She pushes the book against a...

Question:

A student places her 440 g physics book on a frictionless table. She pushes the book against a spring, compressing the spring by 6.80 cm, then releases the book. What is the book's speed as it slides away? The spring constant is 1500 N/m.

Conservation of mechanical energy:

According to the theory of conservation of mechanical energy, the initial and final mechanical energies of the system is conserved.

Answer and Explanation:

The following are the given:

{eq}m = 0.440\ \rm kg \\ x = 0.068\ \rm m \\ k = 1500\ \rm N/m \\ {/eq}

Using energy conservation:

{eq}\begin{align} KE = U_{el} \\ \dfrac{1}{2}mv^2 = \dfrac{1}{2}kx^2 \\ (0.440\ \rm kg)()^2 = (1500\ \rm N/m)(0.068\ \rm m)^2 \\ v = 15.2\ \rm m/s \end{align} {/eq}


Learn more about this topic:

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Conservation of Mechanical Energy

from AP Physics 1: Exam Prep

Chapter 8 / Lesson 8
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