A system consisting of 1 kg of H_2O undergoes a power cycle composed of the following processes:...


A system consisting of 1 kg of {eq}\displaystyle H_2O {/eq} undergoes a power cycle composed of the following processes:

Process 1-2: Constant-pressure heating at 10 bar from saturated vapor.

Process 2-3: Constant-volume cooling to p3 = 5 bar, T3 = 160°C.

Process 3-4: Isothermal compression with {eq}\displaystyle Q_{34} {/eq} = -815.8 kJ.

Process 4-1: Constant-volume heating.

Sketch the cycle on T-v and p-v diagrams. Neglecting kinetic and potential energy effects, determine the thermal efficiency.

Heat Pump Cycle (Power Cycle)

The 2nd Law of Thermodynamics shows us the irreversibility of processes. To idealize a heat pump cycle it is necessary to assume the several aspects, it would be impossible to solve any problem without those assumptions. Generally the kinetic and potential energy effects are ignored for all devices. It is also assumed steady-state for all devices.

Tables and diagrams are the tools to determine some properties. There are three single-phase regions: liquid, solid and vapor. The single-phase region can be fixed by any two of the properties: temperature, pressure or specific volume. Within the single-phase regions any property is independent. The two-phase regions coexist two phase: liquid-solid, liquid-vapor, and solid-vapor. Within two-phase regions pressure and temperature are not independent.

Answer and Explanation: 1

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We will assume the following:

-The system is analyzed as a control volume at steady state

-Compressor and expansion valve operate adiabatically


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