# A vertical spring with a spring constant of 460 N/m is mounted on the floor. From directly above...

## Question:

A vertical spring with a spring constant of 460 N/m is mounted on the floor. From directly above the spring, which is unstrained, a 0.29 kg block is dropped from rest. It collides with and sticks to the spring, which is compressed by 3.9 cm in bringing the block to a momentary halt. Assuming air resistance to be negligible, from what height above the compressed spring was the block dropped?

## Principle of Conservation of Energy:

In the presence of conservative forces, total mechanical energy of the system remain conserved, though it transforms from potential energy to kinetic energy and vice versa.

## Answer and Explanation: 1

Become a Study.com member to unlock this answer! Create your account

We are given:

• Spring constant, k = 460 N/m
• mass of block, m = 0.29 kg
• maximum compression in the spring, x = 3.9 cm = {eq}3.9\times 10^{-2}\ m {/eq}

...

See full answer below.

#### Learn more about this topic: Practice Applying Spring Constant Formulas

from

Chapter 17 / Lesson 11
3.4K

In this lesson, you'll have the chance to practice using the spring constant formula. The lesson includes four problems of medium difficulty involving a variety of real-life applications.