Copyright

(a) What is the ionisation energy of a hydrogen atom that is in the n=6 excited state? (b) For a...

Question:

(a) What is the ionisation energy of a hydrogen atom that is in the n=6 excited state?

(b) For a hydrogen atom , determine the ratio of the ionisation energy for the n=6 excited state to the ionisation energy for the ground state.

Ionisation Energy

The ionisation energy of the hydrogen atom is inversely proportional to the square of the excited state. And it is given by the following equation

{eq}\displaystyle E = \dfrac{-13.6}{n^{2}} \ eV {/eq}

Answer and Explanation:

(a)

Now the Ionisation energy for the excited state (n) = 6

{eq}\displaystyle E_{6} = \dfrac{-13.6}{n^{2}} \eV \\ E_{6} = \dfrac{-13.6}{36} = -0.378 \ eV {/eq}

(b)

Now the energy for the ground state

{eq}\displaystyle E_{1} = -13.6 \ eV {/eq}

Now the ratio will be

{eq}\displaystyle \dfrac{E_{6}}{E_{1}} = \dfrac{-0.378}{-13.6} \\ \dfrac{E_{6}}{E_{1}} = \dfrac{1}{36} {/eq}


Learn more about this topic:

Loading...
Excited State in Chemistry: Definition & Overview

from General Studies Science: Help & Review

Chapter 1 / Lesson 5
73K

Related to this Question

Explore our homework questions and answers library