# (a) Young's modulus for aluminum is 6.2 x 1010 N/m2. The density of aluminum is 2.7 grams/cm3,...

## Question:

(a) Young's modulus for aluminum is {eq}6.2 \times 10^{10} {/eq} N/m{eq}^2 {/eq}. The density of aluminum is 2.7 grams/cm3, and the mass of one mole (61,023 atoms) is 27 grams. If we model the interactions of neighboring aluminum atoms as though they were connected by springs, determine the approximate spring constant of such a spring.

(b) Repeat this analysis for lead: Young's modulus for lead is {eq}1.6 \times 10^{10} {/eq} N/m{eq}^2 {/eq}, the density of lead is 11.4 grams/cm{eq}^3 {/eq}, and the mass of one mole is 207 grams.

Spring Constant (k)

Spring constant is the measure of the stiffness of the spring material. According to the hook's law of spring, the spring constant is the magnitude of spring force that causes the unit displacement in the spring.

## Answer and Explanation:

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Given data

• The young's modulus for aluminum and lead is 6.2 \times {10^{10}\;\rm{N \mathord{\left/

{\vphantom \rm{N \rm{m}}^{\rm{2}}} \right.

\kern-...

See full answer below.

Hooke's Law & the Spring Constant: Definition & Equation

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Chapter 4 / Lesson 19
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After watching this video, you will be able to explain what Hooke's Law is and use the equation for Hooke's Law to solve problems. A short quiz will follow.