# An airplane has a mass of 30,000 kg and takes off under the influence of a constant net force of...

## Question:

An airplane has a mass of 30,000 kg and takes off under the influence of a constant net force of 39,500 N. What is the net force that acts on the plane's 81 kg pilot?

## Force:

Suppose an object with some mass is traveling or moving on a floor, then the total force due to the acceleration of the object can be determined by using the following formula.

{eq}F=ma;\ \text{Here,}\ F\ \text{is}\ \text{the}\ \text{force,}\ m\ \text{is}\ \text{the}\ \text{mass,}\ \text{and}\ a\ \text{is}\ \text{the}\ \text{acceleration} {/eq}

Usually, the force is shown by the Newton (N) unit.

## Answer and Explanation: 1

Given- The mass of the airplane is {eq}{{m}_{1}}=30000\ \text{kg} {/eq}, the net force is {eq}F=39500\ \text{N} {/eq}, and the mass of the pilot is {eq}{{m}_{2}}=81\ \text{kg} {/eq}.

By using the following relation, the acceleration is calculated as,

{eq}F={{m}_{1}}a\Rightarrow \left( 39500\ \text{N} \right)=\left( 30000\ \text{kg} \right)a\Rightarrow a=\dfrac{\left( 39500\ \text{N} \right)}{\left( 30000\ \text{kg} \right)}\Rightarrow a=1.31\ \text{m/}{{\text{s}}^{2}} {/eq}

By using the following relation, the net force of the pilot is calculated as,

{eq}{{F}_{1}}={{m}_{2}}a\Rightarrow {{F}_{1}}=\left( 81\ \text{kg} \right)\left( 1.31\ \text{m/}{{\text{s}}^{2}} \right)\Rightarrow {{F}_{1}}=106.1\ \text{N} {/eq}

Thus, the net force of the pilot is 106.1 Newtons.

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Chapter 5 / Lesson 5Force is everywhere and it comes in a variety of sizes, directions, and types. In this video lesson, you'll identify force as well the different types of force that objects may experience.