# At an outdoor market, a bunch of bananas is set into oscillatory motion with an amplitude of...

## Question:

At an outdoor market, a bunch of bananas is set into oscillatory motion with an amplitude of 30.0781 cm on a spring with a spring constant of 15.7711 N/m. The mass of the bananas is 69.6297 kg. What is the speed of the bananas? Answer in units of m/s.

## Conservation of Energy:

When the spring passes its mean position, potential energy of spring is zero and its total energy is in form of kinetic energy.

When the spring is at its extreme position total energy is in form of potential energy. If 'A' is the amplitude of oscillation and 'k' is the spring constant, the maximum potential energy of spring

{eq}U=\dfrac{1}{2} kA^2 {/eq}

## Answer and Explanation:

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#### Learn more about this topic: Hooke's Law & the Spring Constant: Definition & Equation

from

Chapter 4 / Lesson 19
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After watching this video, you will be able to explain what Hooke's Law is and use the equation for Hooke's Law to solve problems. A short quiz will follow.