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Calculate how much is the spring compressed from its unstrained position from the given details.

Question:

The drawing shows a hydraulic chamber with a spring (spring constant = 1280 N/m) attached to the input piston and a rock of mass 35.0 kg resting on the output plunger. The piston and plunger are nearly at the same height, and each has a negligible mass. By how much is the spring compressed from its unstrained position?

Pressure and Hooke's Law:

Pressure is defined as the transfer of momentum of the particle at a certain surface area. It is equal to the ratio of the force and the area of the certain surface. In a mass-spring system, most of these systems follow Hooke's law. Hooke's law is defined as the force on a spring is equal to a certain spring constant multiplied by the displacement of an object from its equilibrium position.

Answer and Explanation:

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In this case, we equate the the pressure on both location, thus, giving us the expression:

{eq}Ps = Pp \\ \displaystyle Fs = \frac{FpAs}{Ap} {/eq}

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Hooke's Law & the Spring Constant: Definition & Equation

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Chapter 4 / Lesson 19
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After watching this video, you will be able to explain what Hooke's Law is and use the equation for Hooke's Law to solve problems. A short quiz will follow.


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