# Calculate ?rH for the following reaction: CH4(g)+4Cl2(g)?CCl4(g)+4HCl(g) Use the following...

## Question:

Calculate ?rH for the following reaction: CH4(g)+4Cl2(g)?CCl4(g)+4HCl(g)

Use the following reactions and given ?rH's.

C(s)+2H2(g)?CH4(g) ?rH=-74.6kJmol-1

C(s)+2Cl2(g)?CCl4(g) ?rH=-95.7kJmol-1

H2(g)+Cl2(g)?2HCl(g) ?rH=-92.3kJmol?

## Hess Law of constant Heat Summation:

Enthalpy of reactions remains constant whether that reaction proceeds in one single step or multiple numbers of steps. When it follows multiple steps, {eq}\Delta {H_{{\rm{rxn}}}} {/eq} is the sum of these all steps. Mostly it is estimated in kJ/mol.

## Answer and Explanation: 1

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**Given Data:**

- The value of enthalpy change for reaction (I) is {eq}- 74.6\;{\rm{kJ}}\;{\rm{mo}}{{\rm{l}}^{ - 1}}. {/eq}

- The value of enthalpy...

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Chapter 13 / Lesson 3Learn about enthalpy of reaction and enthalpy change formula. Understand what Delta H is, the Delta H equation, and how to calculate the enthalpy of reaction.