# Calculate the volume of a 9.00 M HNO_3 stock solution that must be used to prepare 450 mL 0f a...

## Question:

Calculate the volume of a 9.00 M {eq}HNO_3 {/eq} stock solution that must be used to prepare 450 mL 0f a 1.80 M {eq}HNO_3 {/eq} solution.

## Dilution:

The dilution is a physical process done on a solution in order to change the concentration by simply increasing the volume of the solution. We must take note that the number of moles of the solute in the solution does not change.

Determine the volume of the stock solution, {eq}\displaystyle V_1 {/eq}, with a concentration of {eq}\displaystyle M_1 = 9.00\ M {/eq}, to obtain a diluted solution of {eq}\displaystyle V_2 = 450\ mL {/eq} with a concentration of {eq}\displaystyle M_2 = 1.80\ M {/eq}, using the equation, {eq}\displaystyle M_1V_1 = M_2V_2 {/eq}. We solve for {eq}\displaystyle V_1 {/eq} and plug in the given values to determine the answer.

{eq}\begin{align} \displaystyle M_1V_1 &= M_2V_2\\ V_1 &= \frac{M_2V_2}{M_1}\\ &= \frac{1.80\ M\times 450\ mL}{9.00\ M}\\ &= 90.\ mL \end{align} {/eq}