# Consider a household that uses 14,000 kWh of electricity per year and 900 gal of fuel oil during...

## Question:

Consider a household that uses 14,000 kWh of electricity per year and 900 gal of fuel oil during a heating season. The average amount of {eq}CO_2 {/eq}produced is 26.4 lbm/gal of fuel oil and 1.54 lbm/kWh of electricity. If this household reduces its oil and electricity usage by 15 percent by implementing some energy conservation measures, determine the reduction in the amount of {eq}CO_2 {/eq} emissions by that household per year

## Energy Conservation:

Energy conservation is making efforts for decreasing the usage of energy by using fewer energy services. Conserving energy helps the planet and also saves money on energy services.

## Answer and Explanation:

Given Data

• Usage of electricity per year, {eq}14,000\;{\rm{kW}} {/eq}.
• Fuel oil used per year, {eq}900\;{\rm{gal}} {/eq}.
• Fuel oil used to produce {eq}{\rm{C}}{{\rm{O}}_2} {/eq}, {eq}26.4\;{\rm{lbm/gal}} {/eq}.
• Electricity used to produce {eq}{\rm{C}}{{\rm{O}}_2} {/eq}, {eq}1.54\;{\rm{lbm/kWh}} {/eq}.
• Reduction in oil and electricity, {eq}15\% {/eq} .

Calculating the amount of {eq}{\rm{C}}{{\rm{O}}_2} {/eq} produced by the consumption of fuel oil and electricity is,

{eq}\begin{align*} E &= 1.54 \times 14000 + 26.4 \times 900\\ E &= 45320\;{\rm{lbm}} \end{align*} {/eq}

Thus, the amount of emission or {eq}{\rm{C}}{{\rm{O}}_2} {/eq} produced is {eq}45320\,{\rm{lb}} {/eq}.

If household reduces its oil and electricity usage by {eq}15\% {/eq} , then the reduction in the amount of {eq}{\rm{C}}{{\rm{O}}_2} {/eq} emissions per year is,

{eq}R=45320 \times \dfrac{{15}}{{100}} = 6798\;{\rm{lbm}} {/eq}.

Thus, the amount of reduction in emission is {eq}6798\;{\rm{lbm}} {/eq}.