# Consider a simple pendulum with the following characteristics: T = 1.43 s and m = 0.211 kg. a....

## Question:

Consider a simple pendulum with the following characteristics: T = 1.43 s and m = 0.211 kg.

a. What is the value of the angular frequency {eq}\omega {/eq} of the pendulum?

b. What is the length L of the pendulum?

c. How might the period of this pendulum be different id it were moved from Earth to the planet Volunteerius, where the acceleration due to gravity is four times higher than on Earth?

## Simple Pendulum:

A simple pendulum consists of a heavy metal bob hanging from a massless string. Simple pendulum can oscillate to and fro about its mean position. For the small oscillations, its motion can be considered as the simple harmonic motion. The time period of the oscillations is given by;

{eq}T = 2\pi\ \sqrt{\dfrac{L}{g}} {/eq}

Where;

• L is the length of the string of the pendulum.
• g is the acceleration due to gravity.

## Answer and Explanation:

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Given data:

• {eq}\ \ \ T = 1.43\ s {/eq} is the time period of oscillations of the pendulum
• {eq}\ \ m = 0.211\ kg {/eq} is the mass of the pendulum

...

See full answer below.

Pendulums in Physics: Definition & Equations

from

Chapter 11 / Lesson 6
30K

After watching this lesson, you will be able to explain what a pendulum is, why it is an example of simple harmonic motion, and use equations to solve pendulum problems. A short quiz will follow.