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Consider an RV travels 45 km east and stays the night at a KOA. The next day it travels for 3...

Question:

Consider an RV travels 45 km east and stays the night at a KOA. The next day it travels for 3 hours to the north, traveling 110 km. What is the displacement over the two days for the RV?

Answer and Explanation:

The RV made a right-angle turn at the KOA. The two given legs of the travel are therefore the catheti of a right triangle. The total displacement {eq}\Delta {/eq} is equal to the hypotenuse which can be calculated using the Pythagorean theorem: {eq}\Delta = \rm \sqrt{(45~km)^2 + (110~km)^2} = 120~km~. {/eq}


Learn more about this topic:

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Pythagorean Theorem: Definition & Example

from Remedial Algebra I

Chapter 25 / Lesson 2
30K

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