Evaluate the integral using triangles. \int \frac{\sqrt{(x^2-9)}}{x^3} dx


Evaluate the integral using triangles.

{eq}\int \frac{\sqrt{(x^2-9)}}{x^3} {/eq} dx

Indefinite integral:

You have to find the given indefinite integral. You will use the trigonometry substitution method to find the indefinite integral.

Answer and Explanation:

You have given the integral {eq}I = \int {\frac{{\sqrt {\left( {{x^2} - 9} \right)} }}{{{x^3}}}} dx......\left( 1 \right) {/eq}

Using trigonometric...

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Learn more about this topic:

Understanding Trigonometric Substitution

from Math 104: Calculus

Chapter 13 / Lesson 10

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