Evaluate the summation n = 1 to 6 of 2(3)^(n-1)


Evaluate {eq}\sum_{n=1}^{6}2(3)^{n-1} {/eq}

Evaluating Sums:

In mathematics, we can write a sum using summation notation as {eq}\sum_{n=a}^{b}f(n) {/eq}. To evaluate this sum, we evaluate f(n) for all of the integers from n = a to n = b, and then add up the results.

Answer and Explanation:

Evaluating {eq}\sum_{n=1}^{6}2(3)^{n-1} {/eq} gives 728.

To evaluate this sum, we evaluate 2(3)n - 1 for n = 1, 2, 3, 4, 5, and 6, and then we add...

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Learn more about this topic:

Summation Notation: Rules & Examples

from High School Precalculus: Homework Help Resource

Chapter 27 / Lesson 26

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