# Explain in words how you would prepare 250 ml of a 3.000 M solution of Ba(OH)_2 starting from a...

## Question:

Explain in words how you would prepare {eq}\rm 250\ ml {/eq} of a {eq}\rm 3.000\ M {/eq} solution of {eq}\rm Ba(OH)_2 {/eq} starting from a two liter bottle of {eq}\rm 12.000\ M\ Ba(OH)_2 {/eq}.

## Dilution Equation:

The dilution equation relates the initial and final concentrations and volumes of a certain solution that is diluted. The equation for dilution is given below.

{eq}\rm C_1V_1~=~C_2V_2 {/eq}

Where:

• C1 is the concentration of the initial solution
• C2 is the concentration of the final solution
• V1 is the initial volume of the solution.
• V2 is the final volume of the solution.

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Given:

• C1 = 12.000 M
• C2 = 3.000 M
• V2 = 250 mL

Using the dilution equation, we determine the initial volume of stock solution needed as shown.

{eq}\r... Calculating Dilution of Solutions

from

Chapter 8 / Lesson 5
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Learn what a solution is and how to properly dilute a new solution from a stock solution. Learn the dilution equation that combines molarity, the volume of stock solution and desired solution to determine how much stock solution is needed for the new solution.