Find an equation of the plane consisting of all points that are equidistant from (5, 3, -4) and...

Question:

Find an equation of the plane consisting of all points that are equidistant from {eq}(5, 3, -4) {/eq} and {eq}(3, -5, -2) {/eq}, and having {eq}-2 {/eq} as the coefficient of {eq}x {/eq}.

The Equation of a Plane:

First, we need to compute the midpoint between the given points.

Next, compute the vector formed by the given points is normal to the plane to get the desired solution.

Answer and Explanation:

We are given tow points {eq}(5, 3, -4) {/eq} and {eq}(3, -5, -2) {/eq},

The plane contains the midpoint between the given points :

{eq}P= \left(...

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from PSAT Prep: Tutoring Solution

Chapter 10 / Lesson 13
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