Find the antiderivative of \displaystyle\int ( x + 1 ) ( 3 x - 4 ) d x

Question:

Find the antiderivative of {eq}\displaystyle\int ( x + 1 ) ( 3 x - 4 ) d x {/eq}

Integration:

Integration is also known as antiderivative. It is the process of finding the function f(x) giving the function f'(x).

To find the antiderivative of the given function integrate the given function.

Answer and Explanation:

{eq}\displaystyle\int ( x + 1 ) ( 3 x - 4 ) d x\\ \displaystyle\int ( x + 1 ) ( 3 x - 4 ) d x = \displaystyle\int (3x^2+3x-4x-4)dx\\ \displaystyle\int (3x^2-x-4)dx = 3\frac{x^3}{3} - \frac{x^2}{2}-4x + c= x^3 - \frac{x^2}{2}-4x+c {/eq} 'c' is the constant of integration.


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Integration Problems in Calculus: Solutions & Examples

from AP Calculus AB & BC: Homework Help Resource

Chapter 13 / Lesson 13
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