# Find the area in the first quadrant bounded by the coordinate axes and the graph of y =...

## Question:

Find the area in the first quadrant bounded by the coordinate axes and the graph of

$$y = \frac{\sqrt{225 - x^{2}}}{9}$$

## Finding the Area:

The objective is to find the area of the given region.

The general form of area is {eq}\displaystyle A = \int_{a}^{b} y dx {/eq}

By using the given region we have to find the limit for integration and grt a solution,

We have to integrate the function with respect to {eq}\displaystyle dx {/eq}.

## Answer and Explanation:

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Given that:

{eq}\displaystyle y = \frac{\sqrt{225 - x^{2}}}{9} {/eq}

To find area:

{eq}\displaystyle A = \int_{a}^{b} y dx {/eq}

Let us, find...

See full answer below.

#### Learn more about this topic: Work as an Integral

from

Chapter 7 / Lesson 9
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After watching this video, you will be able to solve calculus problems involving work and explain how that relates to the area under a force-displacement graph. A short quiz will follow.