Find the average value of the function on the given interval. f(x) = x + 1; [0, 15]

Question:

Find the average value of the function on the given interval.

{eq}\displaystyle \ f(x) = \sqrt {x + 1}; \quad [0, 15] {/eq}

Average Value of a Function:

Average value of a function {eq}f(x) {/eq} is: {eq}\displaystyle f_{avg} = \dfrac{1}{b-a} \int_{a}^{b} f(x) \ dx {/eq}

To solve the definite integral, we'll apply u-substitution. Next, compute the boundaries to get the average value of the function.

Answer and Explanation:

Now the average value of the function {eq}f(x) = \sqrt {x + 1} {/eq} on the given interval {eq}[0 , 15 ] {/eq} is:

{eq}=\displaystyle...

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from PSAT Prep: Tutoring Solution

Chapter 10 / Lesson 13
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