# Find the magnitude of the gravitational force a 65.4 kg person would experience while standing on...

## Question:

Find the magnitude of the gravitational force a 65.4 kg person would experience while standing on the surface of Earth with a mass of 5.98*10{eq}^{24} {/eq} kg and a radius of 6.37*10{eq}^6 {/eq} m. The universal gravitational constant is 6.673*10{eq}^{-11} N.m^2/kg^2 {/eq}. Answer in units of N

## Gravitational Force

The exerts a gravitational force on the object around it. The massiveness of the Earth enables it to pull objects several kilometers aways towards it. This is also the reason why the projectile motion and free fall formulation works accurately. To solve for the gravitational force in any location in Earth we just substitute the condition in the formula.

$$g = \frac{GM}{r^2}$$

Where

g is the value of gravity

G is the gravitational constant

M is the mass of the earth

r is the distance from the Earth's core

## Answer and Explanation:

Become a Study.com member to unlock this answer! Create your account

Given

{eq}m = 65.4\ kg {/eq} mass of the person

{eq}M = 5.98\times10^{24} kg{/eq} mass of the Earth

{eq}6.37\times10^6\ m {/eq} Radius of the...

See full answer below.

#### Learn more about this topic: Gravitational Pull of the Earth: Definition & Overview

from

Chapter 15 / Lesson 17
29K

Earth's gravitational pull is often misunderstood, but without it, life on Earth would be impossible. In this lesson, we'll define the gravitational pull and give some examples of how it is used. A quiz is provided to test your understanding.