# Force F = ( - 5.0 N ) i + ( 5.0 N ) j acts on a particle with positive vector r...

## Question:

Force {eq}F = (-5.0 \ N) \ \hat{i} \ + \ (5.0\ N) \ \hat{j} {/eq} acts on a particle with positive vector {eq}r=(1.0 \ m) \ \hat{j} \ + \ (5.0 \ m) \ \hat{k} {/eq}.

a) What is the torque on the particle about the origin?

b) What is the angle between the directions of {eq}r {/eq} and {eq}F {/eq}? (If there is no torque, answer 0)

c) What is the angle between the direction of the force and torque? (If there is no torque, answer 0)

## Torque on a rotating body.:

When a force is applied on an object at a distance from a fixed point then this application of force causes the block to move about the fixed axis. This effect of force is called the torque.

Torque is given by the formula:

{eq}\vec{\tau} = \vec{r}\times \vec{F} {/eq}

Where

{eq}\vec{\tau} {/eq} = torque

{eq}\vec{r} {/eq} = position vector

{eq}\vec{F} {/eq}= force vector

## Answer and Explanation:

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Given:

{eq}\vec{F} = (-5.0 \ N) \ \hat{i} \ + \ (5.0\ N) \ \hat{j} {/eq}

{eq}\vec{r}=(1.0 \ m) \ \hat{j} \ + \ (5.0 \ m) \ \hat{k} {/eq}

Part...

See full answer below.

Torque: Definition, Equation & Formula

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Chapter 4 / Lesson 11
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You've probably heard of torque before, perhaps while discussing cars. Now learn what it really is and what it has to do with rotational equilibrium. Then, work through an example problem that combines the two.