\frac{dy}{dt} - \frac{1}{2}y = e^\frac{1}{2}t \sin t


{eq}\frac{dy}{dt} - \frac{1}{2}y = e^\frac{1}{2}t \sin t {/eq}

Solution to Differential Equation:

Differential equation with form {eq}\displaystyle \frac{dy}{dt}+Py=Q {/eq} is called linear differential equation.

Here, P and Q are constants or function of t only.

It's solution will be,

{eq}\displaystyle \:y\left(I.F\right)=\int \:Q\left(I.F\right)dt+C {/eq} with {eq}\displaystyle I.F=e^{\int \:P\:dt} {/eq}

Answer and Explanation:

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Given differential equation is

{eq}\displaystyle \frac{dy}{dt} - \frac{1}{2}y = e^\frac{1}{2}t \sin t {/eq}

which is linear differential equation


See full answer below.

Learn more about this topic:

First-Order Linear Differential Equations


Chapter 16 / Lesson 3

In this lesson you'll learn how to solve a first-order linear differential equation. We first define what such an equation is, and then we give the algorithm for solving one of that form. Specific examples follow the more general description of the method.

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