# Given that the acceleration vector is a (t) = (-25cos(5t))i + (-25sin(5t))j +(1t)k, the initial...

## Question:

Given that the acceleration vector is a (t) = {eq}(-25\cos{5t})i + (-25\sin{5t})j + tk {/eq}, the initial velocity is v (0) = i + k, and the initial position vector is r (0) = i + j + k compute:

A. the velocity vector v(t) = ?

B. The position vector r (t) = ?

## Acceleration, Velocity and Position Vector:

Integrate the acceleration vector to get the velocity vector. Put the initial values. Again integrate the velocity vector to get the position vector. Plug in the initial values of the position vector. You will ge the position vector of the particle,

## Answer and Explanation: 1

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View this answerGiven that the acceleration vector is a (t) = {eq}(-25\cos{5t})i + (-25\sin{5t})j + tk {/eq}, the initial velocity is v (0) = i + k, and the initial...

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Chapter 1 / Lesson 2There's quite a lot of algebra you need to know to do physics. Here we'll review some of the concepts needed for rearranging equations, working with polynomials, and working with exponents.