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How many formula units make up 25.2 g of magnesium chloride?

Question:

How many formula units make up 25.2 g of magnesium chloride?

Expressing the weight of a compound into formula units

Magnesium chloride is used as a catalyst support in producing polyolefins, as a deicing agent, and in nutraceuticals and pharmaceuticals preparations.

Answer and Explanation:

{eq}MgCl_2 anhydrous \\ MgCl_2\cdot 6H_2O {/eq}

Magnesium Chloride is available in anhydrous and hydrated forms. Naturally, their molecular weight differs.

The molecular weight of the Anhydrous Magnesium Chloride is 95.211 g/mol

The molecular weight of the hexahydrate Magnesium Chloride is 203.31 g/mol

For our calculation, we will take the weight of Anhydrous Magnesium Chloride.

95.211 g Anhydrous Magnesium Chloride is 1 g mole

∴ 25.2 g Anhydrous Magnesium Chloride is {eq}\frac{25.2}{95.211}*1 = 0.264675 {/eq}

1mole contains 6.022 140 76 * 10^23 molecules (formula units)

∴ 0.264675 mole contains = 0.264675* 6.02214076*10^23

= 1.593910105653*10^23 formula units


Learn more about this topic:

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Avogadro's Number: Using the Mole to Count Atoms

from Chemistry 101: General Chemistry

Chapter 2 / Lesson 4
97K

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