# How many grams of oxygen would be involved in heating 5 g of potassium trioxochlorate (V)?

## Question:

Calculate the grams of oxygen which would be involved in heating 5 g of potassium trioxochlorate (V).

## Oxygen:

Oxygen is a gas that has the atomic number eight and molar mass is 16u. However, the availability of oxygen is 21 percent on the earth. It is indicated by the upper latter O.

• The mass of oxygen is = 1.96g

#### Calculation:

The chemical equation:

{eq}2KclO_3 \to 2KCl + 3O_2 {/eq}

The chemical equation shows the mole fraction between {eq}KClO_3 {/eq} and {eq}O_2 {/eq} is 2:3.

Molar mass of potassium triochlorate is = 122.55 g/mol.

Hence, the number of moles in 5g: {eq}= \frac{given \ mass}{Molar \ mass} \\ = \frac{5}{122.55} = 0.0408 moles {/eq}

The number of moles in oxygen {eq}= 0.0408 \times \frac{3}{2} = 0.0612moles {/eq}

The molar mass of oxygen = 32 g/mol

The mass of oxygen = {eq}32 \times 0.0612 = 1.96 g {/eq}