How many milliliters of 3.50 M HCl (aq) are required to react with 5.75 g of Zn(s)?

Question:

How many milliliters of 3.50 M HCl (aq) are required to react with 5.75 g of Zn(s)?

Stoichiometry

By making use of stoichiometric calculations, the reactant's amount required can be predicted in terms of mole. By using moles and the concentration of the reactants, its volume required can be calculated.

Answer and Explanation: 1

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Given data:

  • The mass of {eq}{\rm{Zn}}\left( {\rm{s}} \right){/eq} is 5.75 g.
  • The concentration of {eq}{\rm{HCl}}{/eq} is 3.50 M.


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Mole-to-Mole Ratios and Calculations of a Chemical Equation

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Chapter 9 / Lesson 2
132K

Learn about the mole ratio. Understand the definition of mole ratio, how to find mole ratio in stoichiometry, and see examples of using mole ratio in problems.


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