# How many moles of NaI are produced with 3.27 moles BiI_3?

## Question:

How many moles of {eq}NaI {/eq} are produced with {eq}3.27 \ moles \ BiI_3 {/eq} ?

## Molar Ratio:

The molar ratio between two substances allows us to find the equivalent amount of product or reactant for a certain reaction. We acquire the molar ratio by inspecting a given chemical reaction and acquiring the ratio between the coefficients of the involved substances.

We assume the reaction described in this problem is {eq}\displaystyle BiI3 + 3NaOH = Bi(OH)_3 + 3NaI {/eq}. We determine the the number of moles, {eq}\displaystyle n {/eq}, of produced {eq}\displaystyle NaI {/eq}, by multiplying the number of moles of {eq}\displaystyle BiI_3 {/eq} (n = 3.27 moles) to the molar ratio between {eq}\displaystyle BiI_3 {/eq} and {eq}\displaystyle NaI {/eq}. We know that there are {eq}\displaystyle 1\ mol\ BiI_3 {/eq} for {eq}\displaystyle 3\ mol\ NaI {/eq}. We proceed with the solution.

{eq}\begin{align} \displaystyle n_{NaI} &= 3.27\ mol \ BiI_3\times \frac{3\ mol\ NaI}{1\ mol\ BiI_3}\\ &= 9.81\ mol\ NaI \end{align} {/eq} 