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How much work does a supermarket checkout attendant do on a can of soup he pushes 0.310 m...

Question:

How much work does a supermarket checkout attendant do on a can of soup he pushes 0.310 m horizontally with a force of 5.20 N? Express your answer in joules and kilocalories.

Work done:

The work done is defined as :

{eq}\displaystyle{ W=\vec{F}\cdot \vec{d} } {/eq} here {eq}\displaystyle{\vec{F}} {/eq} is the force applied and {eq}\displaystyle{\vec{d}} {/eq} is the displacement of the object

Thus if the force and displacement is in the same direction then the work done is positive.

Answer and Explanation:

The work done by the attendant is :

{eq}\displaystyle{ W=(5.2)(0.31)\\ W=16.12Nm\\ \color{blue} { W=16.12J\\ } } {/eq}


We know that :

{eq}\displaystyle{ 1 cal=4.184J\\ 1kcal=4184J\\ 1J=\frac{1}{4184}kcal\\ 16.12J=\frac{16.12}{4184}kcal\\ \color{red} { =0.0038kcal } } {/eq}


Learn more about this topic:

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Calculating the Value of Work Done (VOWD)

from Business 311: Project Management

Chapter 9 / Lesson 5
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