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If A and B are mutually exclusive events with P(A) = 0.22 and P(B) = 0.34, then P(A Given B) = ?

Question:

If A and B are mutually exclusive events with P(A) = 0.22 and P(B) = 0.34, then P(A Given B) = ?

Mutually exclusive events

The events which do not have common value or intersection value, If event A and B are mutually exclusive events then the event A and B cannot occur simultaneously. For example, when the coin is tossed then the head and tail cannot occur at the same time.

Answer and Explanation:

Given Information

P(A) = 0.22

P(B) = 0.34


Since the events are mutually exclusive,

{eq}P\left( {A \cap B} \right) = 0 {/eq}

The probability for A given B is given as;

{eq}\begin{align*} P\left( {A|B} \right) &= \dfrac{{P\left( {A \cap B} \right)}}{{P\left( B \right)}}\\ &= \dfrac{0}{{0.34}}\\ &= 0 \end{align*} {/eq}

Hence, the required probability is 0.


Learn more about this topic:

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Mutually Exclusive in Statistics: Definition, Formula & Examples

from High School Algebra II: Help and Review

Chapter 25 / Lesson 8
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