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If you react one mole of sodium hydroxide with excess copper(II) sulfate, how many moles of...

Question:

If you react one mole of sodium hydroxide with excess copper(II) sulfate, how many moles of copper(II) hydroxides are produced?

Stoichiometry:

The area of study concerned with the quantities of chemical substances produced or required for a certain chemical reaction is stoichiometry. The stoichiometric coefficients of the balanced chemical equation relate the quantities of substances with each other.

Answer and Explanation:

We start by establishing the balanced chemical reaction.

{eq}2~NaOH(aq)~+~CoSO_4(aq)~\to~Cu(OH)_2(aq)~+~Na_2SO_4(aq) {/eq}

To determine the moles of copper (II) hydroxide produced, we use the stoichiometric coefficients from the balanced chemical equation.

{eq}1~mol~NaOH\times\frac{1~mol~Cu(OH)_2}{2~mol~NaOH}~=~0.5~mol~Cu(OH)_2 {/eq}

Thus, 0.5 mol of copper (II) hydroxide is produced.


Learn more about this topic:

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Mole-to-Mole Ratios and Calculations of a Chemical Equation

from Chemistry 101: General Chemistry

Chapter 9 / Lesson 2
351K

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