In a game, a toy car slides down a slop. If the top of the slope is 2 m higher than the foot of...

Question:

In a game, a toy car slides down a slop. If the top of the slope is 2 m higher than the foot of the slope, how fast will the car be moving when it reaches the foot? Assume that all of its g.p.e is transformed to k.e

Conservation of Energy:

Conservation of Energy is given by the equation,

{eq}K_1 + U_1 = K_2 + U_2 {/eq}

where {eq}K = \frac{1}{2}mv^2 {/eq} and {eq}U = mgh {/eq}

Answer and Explanation:

Given:

height = 2 m

Solution:

The Conservation of Energy is written as:

{eq}KE = PE {/eq}

where {eq}K = \frac{1}{2}mv^2 {/eq} and {eq}U = mgh {/eq}

{eq}\frac{1}{2}mv^2 = mgh {/eq}

We can cancel out the mass (m),

{eq}\frac{1}{2}v^2 = gh {/eq}

Plugging in the values:

{eq}\frac{1}{2}v^2 = (9.81 \ m/s^2)(2 m) {/eq}

{eq}v^2 = \frac{(9.81 \ m/s^2)(2 m)}{\frac{1}{2}} {/eq}

{eq}v = 6.26 \ m/s {/eq}


Learn more about this topic:

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Energy Conservation and Energy Efficiency: Examples and Differences

from Geography 101: Human & Cultural Geography

Chapter 13 / Lesson 9
108K

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