# In the following reaction, how many grams of ammonia (NH_3) will produce 300 grams of N_2? 4NH_3...

## Question:

In the following reaction, how many grams of ammonia {eq}(NH_3) {/eq} will produce 300 grams of {eq}N_2? 4NH_3 + 6NO \to 5N_2 + 6H_2O. {/eq}

## Stoichiometry:

The area of study primarily concerned with the quantities of chemical species reacted and produced in a certain chemical reaction is stoichiometry. The balanced chemical equation gives the molar ratios needed in all stoichiometric calculations.

To solve problems in stoichiometry, we establish the balanced chemical equation for given reaction.

{eq}4NH_3 + 6NO \to 5N_2 + 6H_2O {/eq}

We also take note of the molar mass of the following substances.

{eq}N_2~=~28\frac{g}{mol} {/eq}

{eq}NH_3~=~17\frac{g}{mol} {/eq}

We determine the grams of ammonia required by using the stoichiometric coefficients of the balanced chemical equation along with the molar mass of nitrogen and ammonia.

{eq}300~g~NH_3\times\frac{1~mol~NH_3}{17~g}\times\frac{5~mol~N_2}{4~mol~NH_3}\times\frac{17~g}{1~mol~NH_3}~=~375~g~NH_3 {/eq}

Therefore, we need 375 g of ammonia to react with excess nitrogen monoxide to produce 300 g of nitrogen.