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In the following reaction, how many grams of ammonia (NH_3) will produce 300 grams of N_2? 4NH_3...

Question:

In the following reaction, how many grams of ammonia {eq}(NH_3) {/eq} will produce 300 grams of {eq}N_2? 4NH_3 + 6NO \to 5N_2 + 6H_2O. {/eq}

Stoichiometry:

The area of study primarily concerned with the quantities of chemical species reacted and produced in a certain chemical reaction is stoichiometry. The balanced chemical equation gives the molar ratios needed in all stoichiometric calculations.

Answer and Explanation:

To solve problems in stoichiometry, we establish the balanced chemical equation for given reaction.

{eq}4NH_3 + 6NO \to 5N_2 + 6H_2O {/eq}

We also take note of the molar mass of the following substances.

{eq}N_2~=~28\frac{g}{mol} {/eq}

{eq}NH_3~=~17\frac{g}{mol} {/eq}

We determine the grams of ammonia required by using the stoichiometric coefficients of the balanced chemical equation along with the molar mass of nitrogen and ammonia.

{eq}300~g~NH_3\times\frac{1~mol~NH_3}{17~g}\times\frac{5~mol~N_2}{4~mol~NH_3}\times\frac{17~g}{1~mol~NH_3}~=~375~g~NH_3 {/eq}

Therefore, we need 375 g of ammonia to react with excess nitrogen monoxide to produce 300 g of nitrogen.


Learn more about this topic:

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Mass-to-Mass Stoichiometric Calculations

from Chemistry 101: General Chemistry

Chapter 9 / Lesson 3
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