Let f(x) = 7x^2 - 2 to find the following value. f(t + 1).


Let {eq}f(x) = 7x^2 - 2 {/eq} to find the following value.

{eq}f(t + 1) {/eq}

Value of a Function:

In this problem, we will replace {eq}x {/eq} with {eq}(t+1) {/eq} to get {eq}f(t+1). {/eq}

Next, we'll factor {eq}(t+1)^2 =t^2+2t+14 {/eq} and simplify to get the desired solution.

Answer and Explanation:

We are given:

{eq}f(x) = 7x^2 - 2 {/eq}

Replace {eq}x {/eq} with {eq}(t+1) {/eq}, we get:

{eq}\Rightarrow f(t+1) = 7(t+1)^2 - 2 {/eq}


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from PSAT Prep: Tutoring Solution

Chapter 10 / Lesson 13

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