Light waves with two different wavelengths, 632 nm and 474 nm, pass simultaneously through a...
Question:
Light waves with two different wavelengths, 632 nm and 474 nm, pass simultaneously through a single slit whose width is {eq}4.58 \times 10^{-5} {/eq} m and strike a screen 1.80 m from the slit. Two diffraction patterns are formed on the screen. What is the distance (in cm) between the common center of the diffraction patterns and the first occurrence of the spot where a dark fringe from one pattern falls on top of a dark fringe from the other pattern?
Fringe Width:
The term which indicates the separation distance among any two particular fringes is represented as fringe width. Fringe width relies on the light beam's wavelength, which means that fringe width alters with a variation in wavelength.
Answer and Explanation: 1
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Given Data:
- The wavelength of first light is {eq}\lambda = 632\;{\rm{nm}}{/eq}.
- The wavelength of second light is {eq}\lambda ' =...
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Chapter 23 / Lesson 2Wave-particle duality means that light and sub-atomic particles can also behave as waves, hence the duality. Study the definition of wave-particle duality, the Davisson-Germer Experiment, the de Broglie wavelength, and an example calculation.
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