Solve the following system of equations: x+2z=2 2y-z=3 x+2y+4z=-1


Solve the following system of equations:

{eq}x+2z=2 \\ 2y-z=3 \\ x+2y+4z=-1 {/eq}

System of Equations:

A system of three equations in three variables is solved by many ways, namely elimination method, substitution method, Cramer's Rule, Gauss Elimination method. Here, we substituted the value of x and y in terms of y using first and second equation and substituted them into the third equation, yielding the value of z. The value of z is then used to obtain the value of x and y.

Answer and Explanation:

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Given the system

{eq}\displaystyle x+2z=2 \\ 2y-z=3 \\ x+2y+4z=-1 {/eq}

{eq}\displaystyle x+2z=2 \Rightarrow x=2-2z \\ \displaystyle 2y-z=3...

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