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Solve the given differential equation. (6x) dx + dy = 0. (Use C as the arbitrary constant.)

Question:

Solve the given differential equation.

{eq}(6x) \, \mathrm{d}x + \, \mathrm{d}y = 0 {/eq}

(Use {eq}C {/eq} as the arbitrary constant.)

First Order Differential Equations:

An ordinary differential equation of first order and first degree can be written as:

{eq}y'=\displaystyle \frac{dy}{dx}=f\left( x , y\right) {/eq}

or in the form: {eq}M \ dx + N \ dy =f\left( x , y\right) {/eq} , where {eq}M = M\left( x,y\right) , N= N\left( x,y\right) {/eq}

To solve this problem, we'll integrate both sides and add constant.

Answer and Explanation:

We are given:

{eq}(6x) \, \mathrm{d}x + \, \mathrm{d}y = 0 {/eq}

Integrating both sides:

{eq}\displaystyle \Rightarrow \int 6x \, \mathrm{d}x =...

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from PSAT Prep: Tutoring Solution

Chapter 10 / Lesson 13
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