Solve the initial-value problem. {eq}\frac {d^3y}{dx^3} = 7 {/eq}; y"(0) = -3, y'(0) = 5, y(0) = 5

Question:

Solve the initial-value problem. {eq}\frac {d^3y}{dx^3} = 7 {/eq}; y"(0) = -3, y'(0) = 5, y(0) = 5

Initial-value problem:

The initial-value problem is the part of the differential equation. This process is used to find the initial condition of the unknown function. This is why it is called initial-value problem.

Answer and Explanation: 1

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We have,

{eq}\displaystyle \frac {d^3y}{dx^3} = 7 {/eq}

Integrating the equation both sides with respect to {eq}x {/eq} we get,

{eq}\displaystyle...

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Determine the Initial Value of a Function

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Chapter 4 / Lesson 5
24K

Learn the definition of the initial value of a function. Understand how to find the initial value. Using examples, practice calculating the initial value for the given function.


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