Solve the initial-value problem. {eq}\frac {d^3y}{dx^3} = 7 {/eq}; y"(0) = -3, y'(0) = 5, y(0) = 5

## Question:

Solve the initial-value problem. {eq}\frac {d^3y}{dx^3} = 7 {/eq}; y"(0) = -3, y'(0) = 5, y(0) = 5

## Initial-value problem:

The initial-value problem is the part of the differential equation. This process is used to find the initial condition of the unknown function. This is why it is called initial-value problem.

## Answer and Explanation: 1

Become a Study.com member to unlock this answer! Create your account

View this answerWe have,

{eq}\displaystyle \frac {d^3y}{dx^3} = 7 {/eq}

Integrating the equation both sides with respect to {eq}x {/eq} we get,

{eq}\displaystyle...

See full answer below.

#### Ask a question

Our experts can answer your tough homework and study questions.

Ask a question Ask a question#### Search Answers

#### Learn more about this topic:

from

Chapter 4 / Lesson 5Learn the definition of the initial value of a function. Understand how to find the initial value. Using examples, practice calculating the initial value for the given function.