# Steam enters an adiabatic turbine at 10 Mpa and 400^oC and leaves at 20 kPa with a quality of 90%...

## Question:

Steam enters an adiabatic turbine at {eq}10 Mpa{/eq} and {eq}400^oC{/eq} and leaves at {eq}20 kPa{/eq} with a quality of 90% of vapor. Neglecting the changes in kinetic and potential energies, given the enthalpy of steam at {eq}10 MPa{/eq} and {eq}400^oC{/eq} is {eq}3096.5 kJ/kg{/eq}. Enthalpies of saturate vapor and liquid at {eq}20 kPa{/eq} are {eq}2358.3 {/eq} and {eq}251.4 kJ/kg{/eq}, respectively. Determine the mass flow rate required for a power output of {eq}5 MW (5000 kJ/s){/eq}:

a) 13.838 {eq}kg/s{/eq}

b) 10.452 {eq}kg/s{/eq}

c) 5.27 {eq}kg/s{/eq}

d) 1.916 {eq}kg/s{/eq}

e) 8.314 {eq}kg/s{/eq}

## Adiabatic Turbine:

We always assume that flow through a turbine is steady. Since this one is an adiabatic turbine, there will be no heat transfer. And since there's only one inlet, the mass coming in must be equal to the mass going out according to the law of conservation of mass.

## Answer and Explanation:

We're given that:

{eq}At\ P_1= 10\ MPa,\ h_1= 3096.5\ Kj/Kg\\ At\ P_2= 20\ MPa,\ h_f=\ 251.4\ Kj/Kg\ and\ h_g= 2358.3\ Kj/Kg\\ x=0.9 {/eq}

Let'...

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Chapter 17 / Lesson 12
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