# Suppose an earthquake shakes you with a frequency of 9.5 Hertz as it passes and continues on to...

## Question:

Suppose an earthquake shakes you with a frequency of {eq}9.5 \ Hz {/eq} as it passes and continues on to another city {eq}75 \ km {/eq} away, which it reaches in {eq}15 \ s {/eq}.

What is the wavelength of the earthquake, in meters?

## Earthquake:

Earthquake is a geological phenomenon that refers to the sudden shaking of the Earth's surface caused by seismic waves passing through Earth's rocks. These seismic waves result from the sudden release of energy in the Earth's lithosphere.

Given:

{eq}f = 9.5 \ Hz {/eq} Frequency of the Earthquake

{eq}d = 75 \ km = 75000 \ m {/eq} Distance traveled by the Earthquake

{eq}t = 15 \ s {/eq} Time interval it took the Earthquake to cover the given distance

First, we can determine the average velocity of the Earthquake as,

{eq}v = \frac {d}{t} = \frac {75000 \ m}{15 \ s} = 5000 \frac {m}{s} {/eq}

Using the velocity of the Earthquake and its given frequency, we can solve for its wavelength using the formula given by,

{eq}\lambda = \frac {v}{f} = \frac {5000 \frac {m}{s}}{9.5 \ Hz} = \boxed {526 \ m} {/eq}