Suppose Spider-Man throws a web that is 1.00 m long with a velocity of 0.8c (\gamma = 5/3) with...

Question:

Suppose Spider-Man throws a web that is 1.00 m long with a velocity of 0.8c {eq}(\gamma = 5/3) {/eq} with respect to the Earth. What will be the length of the web as observed by J. Jonah Jameson standing on the Earth?

a. 0.60 m

b. 1.67 m

c. 1.00 m

d. 1.33 m

Relativistic Length:

When the object is moving with a speed comparable to that of the light, then the length of the object seems shorter than actual to the observer, who is at rest.

Answer and Explanation:

Given Data

Length of the Web {eq}(L_{o}) = 1\ m {/eq}

Lorentz factor {eq}(\gamma) = \dfrac{5}{3} {/eq}

Now, the length that would be observed by the observer at the earth

{eq}L = \dfrac{L_{o}}{\gamma} \\ L = \dfrac{1}{\dfrac{5}{3}} \\ L = 0.6\ m {/eq}


Learn more about this topic:

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Theory of Relativity: Definition & Example

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