The 10-lb weight ''A'' is supported by the cord ''AC'' and roller ''C''. and by spring ''AB''. If...


The 10-lb weight A is supported by the cord AC and roller C. and by spring AB. If the spring has an unstretched length of 8 in. and the weight is in equilibrium when d = 4 in. Determining the stiffness k of the spring.

Hooke's Law:

The spring extends on applying the tensile force and gets compressed due to the compressive force. The force responsible for the deformation of the spring is linearly proportional to the stretch or compression in the spring. Mathematically:

{eq}\rm F=kx {/eq}


  • {eq}k {/eq} is the stiffness of the spring
  • {eq}x {/eq} is the stretch or compression in the spring

Answer and Explanation: 1

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Given data:

  • {eq}W=\rm 10 \ lb {/eq} is the weight attached at A
  • {eq}F_{AB} {/eq} is the spring force
  • {eq}k {/eq} is the spring constant
  • {eq}x {...

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Learn more about this topic:

Hooke's Law & the Spring Constant: Definition & Equation


Chapter 4 / Lesson 19

After watching this video, you will be able to explain what Hooke's Law is and use the equation for Hooke's Law to solve problems. A short quiz will follow.

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