The combustion of propane may be described by the chemical equation...


The combustion of propane may be described by the chemical equation C3H8(g)+5O2(g)---->3CO2(g)+4H2O(g).

How many grams of O2 are needed to completely burn 71.3g of C3H8(g)

Combustion of Propane

Propane is a hydrocarbon, it is generally used as a LPG (Liquefied Petroleum Gas). It acts as a fuel which burns to give energy. Burning or Combustion of propane can be Complete or Incomplete. When the surrounding air carries enough oxygen, propane burns completely to give carbon dioxide and water along with the release of a high amount of heat energy. While, in the lack of oxygen, Incomplete Combustion of propane takes place to form carbon dioxide, water, carbon monoxide, and heat.

Answer and Explanation:

Complete Combustion of Propane :

{eq}C_{3}H_{8}(g)\ +\ 5O_{2}\ \rightarrow\ 3CO_{2}(g)\ +\ 4H_{2}O(g) {/eq}

Mass of propane used = 71.3 g


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Learn more about this topic:

Combustion Reaction: Definition & Examples

from Chemistry: High School

Chapter 3 / Lesson 4

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