The compound potassium iodide is a strong electrolyte. Write the reaction when solid potassium...

Given Data:

• Potassium iodide is a strong electrolyte
• Potassium iodide is put into the water

Hence, the potassium iodide is a strong electrolyte so, the ions will be completely dissociated into the water (aqueous solution).

So, the below chemical equation shows the dissociation of ions while we put potassium iodide in the water.

{eq}{\rm{KI}}\left( s \right) \to {{\rm{K}}^ + }\left( {aq} \right) + {{\rm{I}}^ - }\left( {aq} \right) {/eq}

Here, {eq}s {/eq} represent solid state, and {eq}aq {/eq} shows the aqueous solution.

We get potassium and iodine ions while putting the given compound in the water.

Thus, the required reaction is {eq}{\rm{KI}}\left( s \right) \to {{\rm{K}}^ + }\left( {aq} \right) + {{\rm{I}}^ - }\left( {aq} \right). {/eq}