# The electric field times the electric charge of a particle gives the electric force acting on the...

## Question:

The electric field times the electric charge of a particle gives the electric force acting on the particle. The charge has units of coulombs {eq}(C) {/eq} and the force is expressed in newtons {eq}(N) {/eq}. Suppose you are solving a physics problem in which you calculate an electric field. Which of these is a unit that your answer might have?

a. {eq}N {/eq}

b. {eq}Ns {/eq}

c. {eq}N/C {/eq}

d. {eq}NC {/eq}

## Electric Field:

The intensity of the electric field is defined by knowing the electrostatic force (measured in Newton) applied to the particular charged particle and charge (measured in Coulombs) on it. The unit of the electric field is also derived according to the force and charge.

## Answer and Explanation:

**Given Data**

- The electric field times the electric charge of a particle gives the electric force

The expression for the electric force is,

{eq}F = qE {/eq}

Here, the charge is {eq}q {/eq} and electric filed is {eq}E. {/eq}

Substitute the given units of the force and charge.

{eq}\begin{align*} {\rm{N}} &= {\rm{C}}\left( E \right)\\ E &= \dfrac{{\rm{N}}}{{\rm{C}}} \end{align*} {/eq}

Thus, the electric field is measured in {eq}{\rm{N/C}} {/eq}, so the option **c** is correct.

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