Copyright

The following is an engineering stress (?) versus engineering strain (?) curve for an engineering...

Question:

The following is an engineering stress ({eq}\sigma {/eq}) versus engineering strain ({eq}\epsilon {/eq}) curve for an engineering material. The stress and strain at points A, B, C, D, E are {eq}(\sigma_ e = 38 \ kpsi, \epsilon_e =0.0013), (\sigma_ e =36 kpsi, \epsilon_e =0.00131), (\sigma_ e =52 kpsi, \epsilon_e =0.0038), (\sigma_ e=63 kpsi, \epsilon_e =0.2), and (\sigma_ e =54 kpsi, \epsilon_e =0.3) {/eq}, respectively. CF line is parallel to the AO line.

Determine the upper yield strength, lower yield strength, modulus of elasticity, 0.2% offset yield strength, ultimate tensile strength, the amount of elastic strain and plastic strain at point C. Also, determine the true stress and true strain at point D.

The partsss

Hooke's Law:

The stress generated in the material of concern has a proportional fashion dependency on the quantity of strain generated. This statement is what is widely referred to as Hooke's law. This proportionality is replaced by a constant, which is designated as modulus of elasticity. A material shows a negligible amount of plastic strain generated in this region of proportional dependency on a stress-strain curve.

Answer and Explanation:

Become a Study.com member to unlock this answer! Create your account

View this answer


Given Data

  • The engineering stress at point A is: {eq}{\sigma _{eA}} = 38\;{\rm{kpsi}} {/eq} .
  • The engineering strain at point A is:...

See full answer below.


Learn more about this topic:

Loading...
Hooke's Law & the Spring Constant: Definition & Equation

from

Chapter 4 / Lesson 19
199K

After watching this video, you will be able to explain what Hooke's Law is and use the equation for Hooke's Law to solve problems. A short quiz will follow.


Related to this Question

Explore our homework questions and answers library