The selling price for a classic speedboat is $12,000, which is $2,500 less than two times its...

Question:

The selling price for a classic speedboat is $12,000, which is $2,500 less than two times its original price.

What was the original price of the speedboat?

Word Problems in Algebra:

We use Algebra in solving many word problems. Here, we assume the unknown quantity to be a variable, write an equation based on the given condition and solve it applying the algebraic operations on both sides of the equation.

Answer and Explanation:

Let us assume the selling price and original price of a classic speedboat are {eq}S {/eq} and {eq}O {/eq} respectively.

The problem says, "The selling price for a classic speedboat is $12,000".

So the selling price, {eq}S=12000 {/eq}.

The problem says, "the selling price is $2,500 less than two times its original price".

So we get:

$$S = 2O - 2500 \\[0.3cm] \text{Substitute S= 12000 here}, \\[0.3cm] 12000 = 2O - 2500 \\[0.3cm] \text{Adding 2500 on both sides}, \\[0.3cm] 14500=2O \\[0.3cm] \text{Dividing both sides by 2}, \\[0.3cm] 7250=O $$

Therefore, the original price is, {eq}\boxed{\mathbf{\$ 7,250}} {/eq}.


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