# The selling price for a classic speedboat is $12,000, which is$2,500 less than two times its...

## Question:

The selling price for a classic speedboat is $12,000, which is$2,500 less than two times its original price.

What was the original price of the speedboat?

## Word Problems in Algebra:

We use Algebra in solving many word problems. Here, we assume the unknown quantity to be a variable, write an equation based on the given condition and solve it applying the algebraic operations on both sides of the equation.

Let us assume the selling price and original price of a classic speedboat are {eq}S {/eq} and {eq}O {/eq} respectively.

The problem says, "The selling price for a classic speedboat is $12,000". So the selling price, {eq}S=12000 {/eq}. The problem says, "the selling price is$2,500 less than two times its original price".

So we get:

$$S = 2O - 2500 \\[0.3cm] \text{Substitute S= 12000 here}, \\[0.3cm] 12000 = 2O - 2500 \\[0.3cm] \text{Adding 2500 on both sides}, \\[0.3cm] 14500=2O \\[0.3cm] \text{Dividing both sides by 2}, \\[0.3cm] 7250=O$$

Therefore, the original price is, {eq}\boxed{\mathbf{\\$ 7,250}} {/eq}. 